Bit Stuffing
o For Example, device A uses one time slot,
while the faster device B uses two slots
o The Time slot length is FIXED
o Therefore data rates should be integer
multiples of each other
o For example, we can accommodate a device
that is 5 times faster than the other device
by
giving it five slots to one for each of the other devices
o We
cannot accommodate a
device which is
five and a
half times faster
using this
method
because we cannot introduce half a time slot into a frame
o When the speeds are not integer multiples
of each other, they can be made to behave
as
if they were
o This is done by a technique known as BIT
STUFFING
o In bit stuffing, MUX adds extra bits to a
device
o For Example, if we have one device with a
bit rate of 2.75 times that of other devices,
we
can add enough bits to raise this rate to 3 times that of others
o The extra bits are then discarded by the
Demultiplexer
Asynchronous
TDM
o Synchronous TDM does not guarantee full
utilization of the timeslots
o Because the time slots are fixed and pre
assigned, whenever a connected device is not
transmitting, the
corresponding slot is
empty and much
of the channel
capacity is
wasted
o For
Example, imagine that
we have multiplexed
the o/p of 20 identical
computers
onto
a single line
o Using synchronous TDM, the speed of that
line must be at least 20 times the speed of
each
i/p line
o But what if only 10 computers are in use
at a time?
o Half of the capacity of the line is wasted
o Asynchronous TDM or Statistical TDM is
designed to avoid this type of waste
o Asynchronous means flexible or Not fixed
o In
an asynchronous system,
if we have
'n' input lines,
the frame contains
no more
than
'm' slots, where m is less than n
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o Fig. shows a system with 5 I/p lines
sharing a link using Asynchronous TDM
o Frame size is 3 slots per frame
o Fig shows how MUX handles 3 levels of
traffic
o In the first case, only 3 of the 5
computers have data to send
o In the second case, 4 lines are sending
data
o In the third case, all devices are
sending data
o In
each case, MUX
scans the devices
in order from 1
to 5 filling
time slots as
it
encounters
data to be sent
Asynchronous TDM Figure 1
o In the first case, the 3 active i/p lines
correspond to the 3 slots in each frame
o For the first 4 frames, the I/p is
symmetrically distributed among all the devices.
th
o By the 5 frame however, devices 3 and 5 have
completed their transmission but
device
1 still has two characters to go
Asynchronous TDM Figure 2
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