Routing (Continued)
Shortest Path Algorithm
1. Dijktstra's Algorithm:We now start at B, and examine all nodes adjacent to it. If the sum of the label on B and the distance from B to the node being considered is less than the label on the node, we have a shorter path, so the node is relabeled. After all the nodes adjacent to the working node have been inspected and the tentative labels changed if possible, the entire graph is searched for the tentatively labeled node with the smallest value. This node is made permanent and becomes the working node for the next round. The Figure. 1 shows the first five steps of the algorithm.
Note: Dijkstra's Algorithm is applicable only when cost of all the nodes is non-negative.
2. Bellman Ford's Algorithm:
We look at the distributed version which works on the premise that the information about far away nodes can be had from the adjoining links.
The algorithm works as follows.
- Compute the link costs from the starting node to every directly connected node .
- Select the cheapest links for every node (if there is more than one) .
- For every directly connected node, compute the link costs for all these nodes.
- Select the cheapest route for any node .
Repeat until all nodes have been processed.
Routing algorithms based on Dijkstra's algorithm are called Link State Algorithms. Distance Vector Protocols are based on distributed Bellman's algorithm. In the former we are sending little information to many nodes while in the latter we send huge information to few neighbors.
Count-to-Infinity problem:
Suppose the link between A and E is down events may occur are:
(1) F tells A that it has a path to E with cost 6
(2) A sets cost to E to be 11, and advertise to F again
(3) F sets the cost to E to be 16, and advertise to A again
This cycle will continue and the cost to E goes to infinity. The core of the problem is that when X tells Y that it has a path somewhere ,Y has no way to know whether it itself is on the path.
During this process of counting to infinity, packets from A or F destined to E are likely to loop back and forth between A and F, causing congestion for other packets.
Each node sends one unit of data in unit time except one node Q which sends e (0<e<1) unit of data in unit time. We consider cost of the link as the traffic in that link. We consider P as the only receiver in the ring. Now Ideally we must have nodes left of the diagonal PQ sending data clockwise and that on the right of the PQ counterclockwise as shown in Figure 2. We may assume that Q sends data counterclockwise. Assume that this ideal distribution was achieved at some time. Now we can see that cost of links to the left of PQ are respectively 1,2,3 ..,7 while that on the right of PQ are e,1+e,2+e ..,7+e. Therefore when we reconsider the shortest path the node immediately to the right of Q will see traffic 28 to the left while 28+7e to the right and therefore will start sending data clockwise and same is true for Q also. This will heavily change the traffic on the network. Now the traffic load will shift to the left of PQ and next reconsideration will make a lot of nodes from left of PQ send data counterclockwise. This may keep oscillating and will cost a lot to the network. To prevent these two steps can be taken :
1. Assign a minimum cost to each link.
2. Do not change the route until you get a significant advantage.
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